Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 28: 28

Answer

$\sin\theta=\frac{y}{r}=\frac{-\sqrt 2}{2}$ $\cos\theta=\frac{x}{r}=\frac{-\sqrt 2}{2}$ $\tan\theta=\frac{y}{x}=\frac{-\sqrt 2}{-\sqrt 2}=1$ $\csc\theta=\frac{r}{y}=\frac{2}{-\sqrt 2}=-\sqrt 2$ $\sec\theta=\frac{r}{x}=\frac{2}{-\sqrt 2}=-\sqrt 2$ $\cot\theta=\frac{x}{y}=\frac{-\sqrt 2}{-\sqrt 2}=1$

Work Step by Step

$x=-\sqrt 2$ $y=-\sqrt 2$ $r=\sqrt{(-\sqrt 2)^{2}+(-\sqrt 2)^{2}}=\sqrt {2+2}= 2$
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