Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 28: 11

Answer

$\sin\theta = \frac{y}{r} = \frac{-12}{13}$ $\cos\theta = \frac{x}{r} = \frac{5}{13}$ $\tan\theta = \frac{y}{x} = \frac{-12}{5}$ $\csc\theta = \frac{r}{y} = \frac{13}{12}$ $\sec\theta = \frac{r}{x} = \frac{13}{5}$ $\cot\theta = \frac{x}{y} = \frac{5}{-12}$

Work Step by Step

$x = 5$ $y = -12$ $r = \sqrt {(5)^2 + (-12)^2}$ $r = \sqrt {25 + 144}$ $r = 13$
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