Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 9 - Section 9.1 - Assess Your Understanding - Vocabulary and Skill Building - Page 436: 14

Answer

$\hat{p} = 0.862$, E = 0.009, $x = 9251$

Work Step by Step

Lower Bound: 0.853, Upper Bound: 0.871, n =10,732 i) Find Error Width of Interval = Upper Bound - Lower Bound (0.871 - 0.853) = $\hat{p} + E - (\hat{p} - E)$ 0.018 = 2E E = 0.009 ii) Find $\hat{p}$ $\hat{p} - E = Lower Bound$ $\hat{p} = Lower Bound + E$ $\hat{p} = 0.853 + 0.009$ $\hat{p} = 0.862$ iii) Find $x$ $\hat{p} = \frac{x}{n}$ $x = n\hat{p}$ $x = 10,732 \times 0.862$ $x = 9251$
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