Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 9 - Section 9.1 - Assess Your Understanding - Vocabulary and Skill Building - Page 436: 11

Answer

$\hat{p} = 0.225$, E = 0.024, $x$ = 270

Work Step by Step

Lower Bound: 0.201, Upper Bound: 0.249, n =1200 i) Find Error Width of Interval = Upper Bound - Lower Bound (0.249 - 0.201) = $\hat{p} + E - (\hat{p} - E)$ 0.048 = 2E E = 0.024 ii) Find $\hat{p}$ $\hat{p} - E = Lower Bound$ $\hat{p} = Lower Bound + E$ $\hat{p} = 0.201 + 0.024$ $\hat{p} = 0.225$ iii) Find $x$ $\hat{p} = \frac{x}{n}$ $x$ = $n\hat{p}$ $x$ = 1200 x 0.225 $x$ = 270
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