Chapter 9 - Section 9.1 - Assess Your Understanding - Vocabulary and Skill Building - Page 436: 10

$z_{\frac{α}{2}}=1.75$

$level~of~confidence=(1-α).100$% $92$% $=(1-α).100$% $0.92=1-α$ $α=0.08$ $z_{\frac{α}{2}}=z_{0.04}$ If the area of the standard normal curve to the right of $z_{0.04}$ is 0.04, then the area of the standard normal curve to the left of $z_{0.04}$ is $1−0.04=0.96$ According to Table V, the z-score which gives the closest value to 0.96 is 1.75.