Answer
See the picture.
Work Step by Step
$P(x)={}_nC_{x}~p^x~(1-p)^{n-x}$
n = 8, p = 0.5 and 1 - p = 0.5
$P(0)={}_8C_{0}\times0.5^0\times0.5^{8}=\frac{8!}{0!\times8!}\times0.5^8=1\times0.5^8=0.003906$
$P(1)={}_8C_{1}\times0.5^1\times0.5^{7}=\frac{8!}{1!\times7!}\times0.5^8=8\times0.5^8=0.03125$
$P(2)={}_8C_{2}\times0.5^2\times0.5^6=\frac{8!}{2!\times6!}\times0.5^8=28\times0.5^8=0.1094$
$P(3)={}_8C_{3}\times0.5^3\times0.5^5=\frac{8!}{3!\times5!}\times0.5^8=56\times0.5^8=0.2188$
$P(4)={}_8C_{4}\times0.5^4\times0.5^4=\frac{8!}{4!\times4!}\times0.5^8=70\times0.5^8=0.2734$
$P(5)={}_8C_{5}\times0.5^5\times0.5^3=\frac{8!}{5!\times3!}\times0.5^8=56\times0.5^8=0.2188$
$P(6)={}_8C_{6}\times0.5^6\times0.5^2=\frac{8!}{6!\times2!}\times0.5^8=28\times0.5^8=0.1094$
$P(7)={}_8C_{7}\times0.5^7\times0.5^1=\frac{8!}{7!\times1!}\times0.5^8=8\times0.5^8=0.03125$
$P(8)={}_8C_{0}\times0.5^8\times0.5^0=\frac{8!}{8!\times0!}\times0.5^8=1\times0.5^8=0.003906$
