Answer
P(3) = 0.2150
Work Step by Step
Using formula $P(x) = _{n}C_{x}p^{x}(1-p)^{(n-x)}$, we have:
P(3) = $_{10}C_{3}0.4^{3}(1-0.4)^{(10-3)}$
= 120. 0.064 . 0.028
= 0.2150
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