Answer
P(17) = 0.0123
Work Step by Step
Using formula $P(x) = _{n}C_{x}p^{x}(1-p)^{(n-x)}$, we have:
P(12) = $_{20}C_{17}0.6^{17}(1-0.6)^{(20-17)}$
= 1140. 0.0002 . 0.0064
= 0.0123
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