Answer
$P(fewer~than~2)=0.642$
If we randomly select 25 visitors to the ER 1000 times, we would expect about 642 trials result in fewer than 2 of 25 will die within 1 year.
Work Step by Step
$P(fewer~than~2)=P(X\lt2)=P(0)+P(1)={}_{25}C_{0}~0.05^0~(0.95)^{25}+{}_{25}C_{1}~0.05^1~(0.95)^{24}=\frac{25!}{0!\times(25-0)!}\times1\times0.95^{25}+\frac{25!}{1!\times(25-1)!}\times0.05\times(0.95)^{24}=1\times1\times0.95^{25}+25\times0.05\times(0.95)^{24}=0.642$
