Answer
$P(x\lt2)=0.558$
Work Step by Step
$P(x\lt2)=P(0)+P(1)=\frac{(0.05\times30)^0}{0!}e^{-0.05\times30}+\frac{(0.05\times30)^1}{1!}e^{-0.05\times30}=\frac{1}{1}e^{-1.5}+\frac{1.5}{1}e^{-1.5}=0.558$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 6 - Review - Review Exercises - Page 356: 12b
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