Answer
$P(2)=0.251$
Work Step by Step
$P(x)=\frac{(λt)^x}{x!}e^{-λt}$
For λ = 0.05 and t = 30:
$P(2)=\frac{(0.05\times30)^2}{2!}e^{-0.05\times30}=\frac{2.25}{2}e^{-1.5}=0.251$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 6 - Review - Review Exercises - Page 356: 12a
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