Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Section 5.2 - Assess Your Understanding - Applying the Concepts: 34b

Answer

$P(not~G)=\frac{36}{38}=\frac{18}{19}\approx0.947$

Work Step by Step

The sample space S = "38 slots". So, N(S) = 38. Let R be the event "red slot" (odd-numbered). So, $N(R) = 18$. Let B be the event "black slot" (even-numbered). So, $N(B) = 18$. Let G be the event "0, 00" . So, $N(G)=2$. The event "the metal ball does not land on green" is the complement of "the metal ball lands on green". So, using the Complement Rule (page 275): $P(not~G) = 1-P(G)=1-\frac{N(G)}{N(S)}=1-\frac{2}{38}=\frac{38}{38}-\frac{2}{38}=\frac{36}{38}=\frac{18}{19}\approx0.947$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.