Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Section 5.2 - Assess Your Understanding - Applying the Concepts - Page 278: 33b

Answer

P(not the 1st day of a month) $=\frac{353}{365}\approx0.967$

Work Step by Step

The sample space: a year (365 days). So, N(S) = 365. The event "a person does not have a birthday on the 1st day of a month" is the complement of "a person has a birthday on the 1st day of a month". Event = "a person has a birthday on the 1st day of a month" = {Jan 1, Feb 1, Mar 1, Apr 1, May 1, Jun 1, Jul, 1, Aug 1, Sep 1, Oct 1, Nov 1, Dec 1}. So, N(1st day of a month) = 12. P(not the 1st day of a month) = 1 - P(1st day of a month) = $1-\frac{N(\text{1st day of a month})}{N(S)}=\frac{365}{365}-\frac{12}{365}=\frac{353}{365}\approx0.967$
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