Answer
$\frac{2}{5},\frac{1}{3},\frac{6}{7}$
Work Step by Step
Let $P(E)$ be the probability of an event $E$. According to the Rules of Probabilities:
$0\leq P(E)\leq1$
$0\leq\frac{2}{5}\leq1$. So, $\frac{2}{5}$ can be the probability of an event.
$0\leq\frac{1}{3}\leq1$. So, $\frac{1}{3}$ can be the probability of an event.
$-\frac{4}{7}\lt1$. So, $-\frac{4}{7}$ can not be the probability of an event.
$\frac{4}{3}\gt1$. So, $\frac{4}{3}$ can not be the probability of an event.
$0\leq\frac{6}{7}\leq1$. So, $\frac{6}{7}$ can be the probability of an event.
