Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Review - Review Exercises - Page 315: 13a

Answer

$P(E)=\frac{1}{19}\approx0.05263$. If we play the game 1900 times, we would expect that the metal ball falls into a green slot about 100 times.

Work Step by Step

The sample space S = {0, 00, 1, 2, 3, ..., 34, 35, 36}. So, $N(S)=38$ Let E be the event "green slot" = {0, 00}. So, $N(E)=2$. $P(E)=\frac{N(E)}{N(S)}=\frac{2}{38}=\frac{1}{19}\approx0.05263$
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