Answer
$P(E)=\frac{9817}{33,722}\approx0.2911$
Work Step by Step
Number of traffic fatalities = 33,722
Let E be the event "alcohol related". According to the text the frequency of E = 9817.
Using the Empirical Approach (page 258):
$P(E)\approx\frac{frequency~of~E}{Number~of~traffic~fatalities}=\frac{9817}{33,722}\approx0.2911$
