Answer
$P(postterm~or~3000~to~3999~grams)=\frac{2,892,467}{4,305,340}=0.6718$
Work Step by Step
The sample space: $4,305,340$ babies born in 2007. So, $N(S)=4,305,340$
$P(postterm)=\frac{242,139}{4,305,340}$
$P(3000~to~3999~grams)=\frac{2,825,549}{4,305,340}$
$P(postterm~and~3000~to~3999~grams)=\frac{175,221}{4,305,340}$
Using the General Addition Rule (page 273):
$P(postterm~or~3000~to~3999~grams)=P(postterm)+P(3000~to~3999~grams)-P(postterm~and~3000~to~3999~grams)=\frac{242,139}{4,305,340}+\frac{2,825,549}{4,305,340}-\frac{175,221}{4,305,340}=\frac{2,892,467}{4,305,340}=0.6718$
