Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Review - Case Study - The Case of the Body in the Bag - Page 319: 9

Answer

$P(victim~and~the~offender~from~different~race)=\frac{1102}{7285}\approx0.1513$

Work Step by Step

$P(both~same~race)=\frac{6183}{7285}\approx0.8487$ The events "victim and the offender from different race" is the complement of "both same race". $P(victim~and~the~offender~from~different~race)=1-P(both~same~race)=1-\frac{6183}{7285}=\frac{7285}{7285}-\frac{6183}{7285}=\frac{1102}{7285}\approx0.1513$
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