Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Review - Case Study - The Case of the Body in the Bag - Page 319: 11

Answer

$P(victim~and~the~offender~of~different~sexes)=\frac{2399}{7285}=0.3293$

Work Step by Step

$P(both~same~sex)=\frac{4886}{7285}\approx0.6707$ The events "victim and the offender of different sexes" is the complement of "both same sex". $P(victim~and~the~offender~of~different~sexes)=1-P(both~same~sex)=1-\frac{4886}{7285}=\frac{7285}{7285}-\frac{4886}{7285}=\frac{2399}{7285}=0.3293$
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