Answer
$P(victim~and~the~offender~from~different~age~category)=\frac{1512}{7285}=0.2075$
Work Step by Step
$P(both~same~age~category)=\frac{5773}{7285}$
The events "victim and the offender from different age category" is the complement of "both same age category".
$P(victim~and~the~offender~from~different~age~category)=1-P(both~same~age~category)=1-\frac{5773}{7285}=\frac{7285}{7285}-\frac{5773}{7285}=\frac{1512}{7285}=0.2075$
