Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Review - Case Study - The Case of the Body in the Bag - Page 319: 8

Answer

$P(both~same~race)=\frac{6183}{7285}\approx0.8487$

Work Step by Step

The sample space: $3026+573+53+57+208+3034+12+49+54+28+97+7+30+27+4+26=7285$ cases. That is: $N(S)=7285$ Now: $N(both~white)=3026$ $N(both~black)=3034$ $N(both~other)=97$ $N(both~Unknown~race)=26$ $P(both~same~race)=P(both~white~or~both~black~or~both~other~or~both~Unknown~race)=P(both~white)+P(both~black)+P(both~other)+P(both~Unknown~race)=\frac{N(both~white)}{N(S)}+\frac{N(both~black)}{N(S)}+\frac{N(both~other)}{N(S)}+\frac{N(both~Unknown~race)}{N(S)}=\frac{3026}{7285}+\frac{3034}{7285}+\frac{97}{7285}+\frac{26}{7285}=\frac{6183}{7285}\approx0.8487$
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