Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 14 - Section 14.2 - Assess Your Understanding - Applying the Concepts - Page 697: 8d

Answer

Confidence interval: $2.021\lt ŷ\lt9.173$ We are 90% confident that the interest rate of Kaleigh is between 2.021 and 9.173 percent.

Work Step by Step

From problem 12 from Section 14.1: $s_e=1.424$ $∑(x_i-x ̅)^2=166.68^2=27782.22$ $x ̅=\frac{545+595+640+675+705+750}{6}=651.67$ $n=6$, so: $d.f.=n-2=4$ $level~of~confidence=(1-α).100$% $90$% $=(1-α).100$% $0.9=1-α$ $α=0.1$ $t_{\frac{α}{2}}=t_{0.05}=2.132$ (According to Table VI, for d.f. = 4 and area in right tail = 0.05) $Lower~bound=ŷ -t_{\frac{α}{2}}.s_e\sqrt {1+\frac{1}{n}+\frac{(x^*-x ̅)^2}{∑(x_i-x ̅)^2}}=5.5967-2.132\times1.424\sqrt {1+\frac{1}{6}+\frac{(730-651.67)^2}{27782.22}}=2.021$ $Upper~bound=ŷ +t_{\frac{α}{2}}.s_e\sqrt {1+\frac{1}{n}+\frac{(x^*-x ̅)^2}{∑(x_i-x ̅)^2}}=5.5967+2.132\times1.424\sqrt {1+\frac{1}{6}+\frac{(730-651.67)^2}{27782.22}}=9.173$
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