Elementary Statistics: Picturing the World (6th Edition)

Published by Pearson
ISBN 10: 0-32191-121-0
ISBN 13: 978-0-32191-121-6

Chapter 5 - Normal Probability Distributions - Review Exercises - Page 287: 44

Answer

Answer: $-z = -1.88$ and $z = 1.88$

Work Step by Step

We know that $P(-z < Z < z) = 0.94$ 1) Area outside the given region: $1 - 0.94 = 0.06$ 2) Thus, the cumulative area is given by $P( Z < -z ) = 0.03$ 3) Use the standard normal table to find the corresponding z score $-z$ $=$ $-1.88 $ Thus, approximately 94% of the distribution's area lies between $-z = -1.88$ and $z = 1.88$
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