#### Answer

Answer: $-z = -1.88$ and $z = 1.88$

#### Work Step by Step

We know that $P(-z < Z < z) = 0.94$
1) Area outside the given region:
$1 - 0.94 = 0.06$
2) Thus, the cumulative area is given by
$P( Z < -z ) = 0.03$
3) Use the standard normal table to find the corresponding z score
$-z$ $=$ $-1.88 $
Thus, approximately 94% of the distribution's area lies between $-z = -1.88$ and $z = 1.88$