Elementary Statistics: Picturing the World (6th Edition)

Published by Pearson
ISBN 10: 0321911210
ISBN 13: 978-0-32191-121-6

Chapter 5 - Normal Probability Distributions - Review Exercises - Page 287: 34

Answer

a) P( 1.8 < x < 2.2)= 0.5762 b) P( 2.1 < x < 2.7) = 0.342 c) P( x > 2.3) = 0.1151

Work Step by Step

PART A i) Find corresponding z scores using z = $\frac{x - \mu }{\sigma}$ z = $\frac{1.8 - 2}{0.25} = -0.8$ z = $\frac{2.2 - 2}{0.25} = 0.8$ ii) P (-0.8 < z < 0.8) = P(z < 0.8) - P(z < -0.8) = 0.7881 - 0.2119 =0.5762 PART B i) Find corresponding z scores $P(2.1 < x < 2.7)$ = $P(\frac{2.1 - 2}{0.25} < z < \frac{2.7 - 2}{0.25})$ = $P(0.4 < z < 2.8)$ ii) Evaluate $P(0.4 < z < 2.8)$ = P(z < 2.8) - P(z < 0.4) = 0.9974 - 0.6554 = 0.342 PART C i) Find corresponding z score $P(x > 2.3) = P(z > \frac{2.3 - 2}{0.25}) = P(z > 1.2)$ ii) Evaluate $P(z > 1.2)$ = 1 - $P(z <1.2)$ = 1- 0.8849 = 0.1151
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