Elementary Statistics: Picturing the World (6th Edition)

Published by Pearson
ISBN 10: 0321911210
ISBN 13: 978-0-32191-121-6

Chapter 5 - Normal Probability Distributions - Review Exercises - Page 287: 39

Answer

Answer: z = 2.455

Work Step by Step

The area 0.993 is not on the standard normal distribution table. However, it falls between the probabilities 0.9929 and 0.9931 which are both on the standard normal distribution table. 0.9929 corresponds to a z score of 2.45 and 0.9931 corresponds to a z score of 2.46. The z score for 0.993 is halfway between those values. So to find the z score corresponding to 0.993: (2.45 + 2.46)/2 = 2.455 Therefore 0.993 corresponds to a z score of 2.455
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