Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 6 - The Normal Distribution - Review Exercises - Section 6-4 - Page 363: 17



Work Step by Step

We have $p=0.173, n=120$ Check $np=20.76\gt5, n(1-p)=99,24\gt5$ We will use normal approximation to the binomial distribution. $\mu=np=20.76, \sigma=\sqrt {np(1-p)}=4.14$ $X1=20.5, X2=34.5, z1=\frac{20.5-20.76}{4.14}=-0.06, z2=\frac{34.5-20.76}{4.14}=3.32$ The probability between z1 and z2 is 0.523
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