Answer
0.126
Work Step by Step
Given $p=0.26, n=60$
we have $np=15.6, n(1-p)=44.4$ both large enough to
allow normal approximation to the binomial distribution.
$\mu=np=15.6, \sigma=\sqrt {np(1-p)}=3.4$
Use $X=19.5, z=\frac{19.5-15.6}{3.4}=1.147$
The probability above this z-score is 0.126