Answer
0.047
Work Step by Step
Given $p=0.2, n=200$
we have $np=40, n(1-p)=160 both larger than 4$
we can use normal approximation to the binomial distribution.
$\mu=np=40, \sigma=\sqrt {np(1-p)}=5.66$
Use $X=49.5, z=\frac{49.5-40}{5.66}=1.678$
The probability above this z-score is 0.047