#### Answer

Variance:15.55
Standard deviation:3.94
Range:16.

#### Work Step by Step

By using the results from before: $\mu=1.89.$
Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(11-1.89)^2+(3-1.89)^2+...+(2-1.89)^2}{18}=15.55.$
Standard deviation=$\sqrt{variance}=\sqrt{15.55}=3.94$
Range=maximum value-minimum value=$11-(-5)=16$.