Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation - Basic Skills and Concepts - Page 108: 17

Answer

Variance:202.44 Standard deviation:14.23 Range:43.

Work Step by Step

By using the results from before: $\mu=(-14.25).$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{((-15)-(-14.25))^2+((-18)-(-14.25))^2+...+(2-(-14.25))^2}{8}=202.44.$ Standard deviation=$\sqrt{variance}=\sqrt{202.44}=14.23$ Range=maximum value-minimum value=$11-(-32)=43$.
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