Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation - Basic Skills and Concepts: 16

Answer

Variance:0.164. Standard deviation:0.405 Range:1.17.

Work Step by Step

By using the results from before: $\mu=0.9382.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(0.38-0.9382)^2+(0.55-0.9382)^2+...+(1.46-0.9382)^2}{11}=0.164.$ Standard deviation=$\sqrt{variance}=\sqrt{0.164}=0.405$ Range=maximum value-minimum value=$1.55-0.38=1.17$.
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