Answer
Variance:0.164.
Standard deviation:0.405
Range:1.17.
Work Step by Step
By using the results from before: $\mu=0.9382.$
Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(0.38-0.9382)^2+(0.55-0.9382)^2+...+(1.46-0.9382)^2}{11}=0.164.$
Standard deviation=$\sqrt{variance}=\sqrt{0.164}=0.405$
Range=maximum value-minimum value=$1.55-0.38=1.17$.