Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation - Basic Skills and Concepts - Page 109: 19

Answer

Variance:925.14 Standard deviation:30.42 Range:79.

Work Step by Step

By using the results from before: $\mu=50.36.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(11-50.36)^2+(3-50.36)^2+...+(2-50.36)^2}{11}=925.14.$ Standard deviation=$\sqrt{variance}=\sqrt{925.14}=30.42$ Range=maximum value-minimum value=88-9=79$.
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