Answer
The variation for Brinks is less.
Work Step by Step
Coefficient of variation=$\frac{standard \ deviation}{mean}$
By using the results from before:
$cv_{B}=\frac{standard \ deviation}{mean}=\frac{0.178}{1.55}=0.1148=11.48$%
$cv_{nB}=\frac{standard \ deviation}{mean}=\frac{0.2214}{1.73}=0.128=12.8$%
The variation for Brinks is less.