Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Section 9.4 - Vectors in Three Dimensions - 9.4 Exercises - Page 658: 42

Answer

$α = 60°$

Work Step by Step

Use the property of Direction Cosines given here: $\cos^2 α + \cos^2 β + \cos^2 γ = 1$ Given that $β = \frac{2\pi}{3}$, $γ = \frac{\pi}{4}$ and α is acute $\cos^2 α + \cos^2 {\frac{2\pi}{3}} + \cos^2 {\frac{\pi}{4}} = 1$ $\cos^2 α + (-0.5)^2 + ({\frac{1}{\sqrt2}})^2 = 1$ $\cos^2 α + 0.25 + 0.5 = 1$ $\cos^2 α = \frac{1}{4}$ $\cos α = +/- 0.5$ $α = 60°$
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