Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Section 9.4 - Vectors in Three Dimensions - 9.4 Exercises - Page 658: 39

Answer

$a_1 = 73.40°$ $a_2 = 64.62°$ $a_3 = 148.997°$

Work Step by Step

The direction angles are determined by the following formula: $\cos {a_x} = \frac{u_x}{|u|}$ (from the book) Given $u = <2, 3, -6>$ Thus $|u| = \sqrt{ 2^2 + (3)^2 + (-6)^2} = \sqrt{4 + 9 + 36} = \sqrt 49 = 7 $ $\cos a_1 = \frac{2}{7}$ $\cos a_2 = \frac{3}{7}$ $\cos a_3 = \frac{-6}{7}$ Solve for each angle. $a_1 = 73.40°$ $a_2 = 64.62°$ $a_3 = 148.997°$
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