Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Section 9.4 - Vectors in Three Dimensions - 9.4 Exercises - Page 658: 14

Answer

$3\sqrt 5$

Work Step by Step

|a|=$\sqrt (1)^2+(-6)^2+(2\sqrt 2)^2$=$\sqrt 45$, |a|=$3\sqrt 5$
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