Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Section 9.4 - Vectors in Three Dimensions - 9.4 Exercises - Page 658: 38

Answer

$a_1 = 65.91°$ $a_2 = 144.74°$ $a_3 = 114.09°$

Work Step by Step

The direction angles are determined by the following formula: $\cos {a_x} = \frac{u_x}{|u|}$ (from the book) Given $u = i - 2j - k$ Thus $|u| = \sqrt{ 1^2 + (-2)^2 + (-1)^2} = \sqrt{1 + 4 + 1} = \sqrt 6 $ $\cos a_1 = \frac{1}{\sqrt 6}$ $\cos a_2 = \frac{-2}{\sqrt 6}$ $\cos a_3 = \frac{-1}{\sqrt 6}$ Solve for each angle. $a_1 = 65.91°$ $a_2 = 144.74°$ $a_3 = 114.09°$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.