Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Section 8.3 - Polar Form of Complex Numbers; De Moivre's Theorem - 8.3 Exercises - Page 611: 86

Answer

$w_0=2(cos~\frac{4\pi}{15}+i~sin~\frac{4\pi}{15})$ $w_1=2(cos~\frac{2\pi}{3}+i~sin~\frac{2\pi}{3})=-1+\sqrt 3i$ $w_2=2(cos~\frac{16\pi}{15}+i~sin~\frac{16\pi}{15})$ $w_3=2(cos~\frac{22\pi}{15}+i~sin~\frac{22\pi}{15})$ $w_4=2(cos~\frac{28\pi}{15}+i~sin~\frac{28\pi}{15})$

Work Step by Step

$r=|z|=\sqrt {a^2+b^2}=\sqrt {(-16)^2+(-16\sqrt 3)^2}=\sqrt {1024}=32$ $tan~θ=\frac{b}{a}=\frac{-16\sqrt 3}{-16}=\sqrt 3$ $θ=\frac{4\pi}{3}$ Polar form: $z=32(cos~\frac{4\pi}{3}+i~sin~\frac{4\pi}{3})$ $w_k=\sqrt[5]{32}[cos(\frac{\frac{4\pi}{3}+2k\pi}{5})+i~sin(\frac{\frac{4\pi}{3}+2k\pi}{5})]$ $w_0=2(cos~\frac{4\pi}{15}+i~sin~\frac{4\pi}{15})$ $w_1=2(cos~\frac{2\pi}{3}+i~sin~\frac{2\pi}{3})=-1+\sqrt 3i$ $w_2=2(cos~\frac{16\pi}{15}+i~sin~\frac{16\pi}{15})$ $w_3=2(cos~\frac{22\pi}{15}+i~sin~\frac{22\pi}{15})$ $w_4=2(cos~\frac{28\pi}{15}+i~sin~\frac{28\pi}{15})$
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