Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Section 8.3 - Polar Form of Complex Numbers; De Moivre's Theorem - 8.3 Exercises - Page 611: 82

Answer

$w_0=\sqrt[6] 2(cos~\frac{\pi}{12}+i~sin~\frac{\pi}{12})$ $w_1=\sqrt[6] 2(cos~\frac{3\pi}{4}+i~sin~\frac{3\pi}{4})$ $w_2=\sqrt[6] 2(cos~\frac{17\pi}{12}+i~sin~\frac{17\pi}{12})$

Work Step by Step

$r=|z|=\sqrt {a^2+b^2}=\sqrt {1^2+1^2}=\sqrt 2$ $tan~θ=\frac{b}{a}=1$ $θ=\frac{\pi}{4}$ Polar form: $z=\sqrt 2(cos~\frac{\pi}{4}+i~sin~\frac{\pi}{4})$ $w_k=\sqrt[3] {\sqrt 2}[cos(\frac{\frac{\pi}{4}+2k\pi}{3})+i~sin(\frac{\frac{\pi}{4}+2k\pi}{3})]$ $w_0=\sqrt[6] 2(cos~\frac{\pi}{12}+i~sin~\frac{\pi}{12})$ $w_1=\sqrt[6] 2(cos~\frac{3\pi}{4}+i~sin~\frac{3\pi}{4})$ $w_2=\sqrt[6] 2(cos~\frac{17\pi}{12}+i~sin~\frac{17\pi}{12})$
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