Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Review - Exercises - Page 623: 49

Answer

$x=\frac{1}{2}( \cos\theta+ 1)$ $y=\frac{1}{2}(\sin\theta + \tan\theta)$

Work Step by Step

From the right triangles in the graph we determine the coordinates of the points $Q$ and $R$: $Q(\cos\theta, \sin\theta)$ $R(1,\tan\theta)$ The point $P$ is middle point of $Q$ and $R$, therefore its coordinates are: $x=\frac{1}{2}( \cos\theta+ 1)$ $y=\frac{1}{2}(\sin\theta + \tan\theta)$ $P\left(\frac{1+\cos\theta}{2},\frac{\sin\theta+\tan\theta}{2}\right)$
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