Answer
(a) See the graph.
(b) $y=2(x-2)^2,~~x\ne2$
Work Step by Step
(a) $t\ne0$. If $t\gt0$, as $t$ increases $x$ decreases. If $t\lt0$, as $t$ increases $x$ decreases.
(b)
$x=\frac{1}{t}+2$
$x-2=\frac{1}{t}$
$\frac{1}{t^2}=(x-2)^2$
$y=\frac{1}{t^2}$
$y=2(x-2)^2,~~x\ne2$
