Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Review - Exercises - Page 623: 41

Answer

$w_0=1$ $w_1=\frac{1}{2}+\frac{\sqrt 3}{2}i$ $w_2=-\frac{1}{2}+\frac{\sqrt 3}{2}i$ $w_3=-1$ $w_4=-\frac{1}{2}-\frac{\sqrt 3}{2}i$ $w_5=\frac{1}{2}-\frac{\sqrt 3}{2}i$

Work Step by Step

$r=|z|=1$ $θ=0~~$ (Posiative real axis) Polar form: $z=1=1(cos~0+i~sin~0)$ $w_k=\sqrt {1}[cos(\frac{0+2k\pi}{6})+i~sin(\frac{0+2k\pi}{6})]$ $w_0=1(cos~0+i~sin~0)=1$ $w_1=1(cos~\frac{\pi}{3}+i~sin~\frac{\pi}{3})=\frac{1}{2}+\frac{\sqrt 3}{2}i$ $w_2=1(cos~\frac{2\pi}{3}+i~sin~\frac{2\pi}{3})=-\frac{1}{2}+\frac{\sqrt 3}{2}i$ $w_3=1(cos~\pi+i~sin~\pi)=-1$ $w_4=1(cos~\frac{4\pi}{3}+i~sin~\frac{4\pi}{3})=-\frac{1}{2}-\frac{\sqrt 3}{2}i$ $w_5=1(cos~\frac{5\pi}{3}+i~sin~\frac{5\pi}{3})=\frac{1}{2}-\frac{\sqrt 3}{2}i$
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