Answer
(a) See the graph.
(b) $(x-1)^2+(y-1)^2=1,~~1\leq x\leq2,~~0\leq y\leq1$
Work Step by Step
(a)
$t=0$:
$x=2$
$y=1$
$t=\frac{\pi}{2}$:
$x=1$
$y=0$
So, the curve move in the clockwise direction.
(b)
$x=1+cos~t$
$cos~t=x-1$
$y=1-sin~t$
$sin~t=1-y$
$cos^2t+sin^2t=1$
$(x-1)^2+(1-y)^2=1$
$(x-1)^2+(y-1)^2=1$
