Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Review - Test - Page 580: 1

Answer

$\tan \theta\sin \theta+\cos \theta=\sec\theta$

Work Step by Step

Start with the left side: $\tan \theta\sin \theta+\cos \theta$ Write everything in terms of cosine: $=\frac{\sin \theta}{\cos \theta}*\sin \theta+\cos \theta$ Rewrite expression to get a common denominator: $=\frac{\sin^2 \theta}{\cos \theta}+\frac{\cos^2\theta}{\cos \theta}$ Add the two fractions and use the identity $\sin^2\theta+\cos^2\theta=1$: $=\frac{\sin^2 \theta+\cos^2\theta}{\cos \theta}$ $=\frac{1}{\cos \theta}$ $=\sec\theta$ Since this equals the right side, the identity has been proven.
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