Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Review - Test - Page 580: 14

Answer

0.34, 2.80

Work Step by Step

$3\sin\theta-1=0$ $3\sin\theta=1$ $\sin\theta=\frac{1}{3}$ Since sine is positive in the first and second quadrants, the only solutions in the interval $[0, 2\pi)$ are $\theta=\sin^{-1}\frac{1}{3}\approx 0.34$ and $\theta=\pi-\sin^{-1}\frac{1}{3}\approx 2.80$.
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