Answer
$\frac{\sqrt 3}{2}$ , $\sqrt 3$
Work Step by Step
Given expression is-
$\sin2\theta$ , $2\sin\theta$
Also given $\theta$ = $\frac{\pi}{3}$
Therefore expression becomes-
$\sin (2\times\frac{\pi}{3})$ , $2\sin\frac{\pi}{3}$
= $\sin \frac{2\pi}{3}$ , $2\sin\frac{\pi}{3}$
= $\frac{\sqrt 3}{2}$ , $2\times\frac{\sqrt 3}{2}$
= $\frac{\sqrt 3}{2}$ , $\sqrt 3$
i.e. $\sin \frac{2\pi}{3}$ = $\frac{\sqrt 3}{2}$
and $2\sin\frac{\pi}{3}$ = $\sqrt 3$
