Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.3 - Trigonometric Functions of Angles - 6.3 Exercises - Page 499: 23

Answer

Exact value of $\tan 750^{\circ}$ = $\frac{1}{\sqrt 3}$ or $\frac{\sqrt 3}{3}$

Work Step by Step

To find exact value of $\tan 750^{\circ}$, let's find its reference angle first. $ 750^{\circ} = 2\times360^{\circ} + 30^{\circ}$ Thus $ 750^{\circ}$ terminates in quadrant I and its reference angle is $30^{\circ}$ As $ 750^{\circ}$ terminates in quadrant I, its $\tan$ will be positive. Therefore by reference angle theorem- $\tan 750^{\circ}$ = $\tan 30^{\circ}$ = $\frac{1}{\sqrt 3}$ = $\frac{\sqrt 3}{3}$
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