Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.3 - Trigonometric Functions of Angles - 6.3 Exercises - Page 499: 34

Answer

Exact value of $\cos \frac{7\pi}{4} = \frac{\sqrt 2}{ 2} $

Work Step by Step

To find exact value of $\cos \frac{7\pi}{4}$, let's find its reference angle first. As $ \frac{7\pi}{4}$ terminates in quadrant IV, The reference angle = $2\pi -\frac{7\pi}{4} $ = $\frac{\pi}{4}$ As $ \frac{7\pi}{4}$ terminates in quadrant IV, its $\cos$ will be positive. Therefore by reference angle theorem- $\cos \frac{7\pi}{4}$ = $\cos\frac{\pi}{4}$ = $\frac{1}{\sqrt 2}$ = $\frac{\sqrt 2}{ 2}$
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