Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.2 - Trigonometry of Right Triangles - 6.2 Exercises - Page 489: 62

Answer

11,379 ft

Work Step by Step

See sketch below Left triangle: 5150 is opposite, $x_{1}$ adjacent to $52^{o}$ $\displaystyle \tan 52^{o}=\frac{5150}{x_{1}}$ $ x_{1}=\displaystyle \frac{5150}{\tan 52^{o}}\approx$4023.62097651$\approx$4024 ft Right triangle: $ x_{2}=\displaystyle \frac{5150}{\tan 35^{o}}\approx$7354.96223472$\approx$7355 $ x_{2}+x_{1}\approx$11,379 ft
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