Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.2 - Trigonometry of Right Triangles - 6.2 Exercises - Page 489: 59

Answer

345 ft

Work Step by Step

The length of the string is the hypotenuse, the height of the kite (x) is the leg opposite to $50^{o}.$ $\displaystyle \sin 50^{o}=\frac{x}{450}$ $ x=450\sin 50^{o}\approx$344.719999404$\approx$ 345 ft
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